Evaluate the following product without multip | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To evaluate $93 	imes 95$ without direct multiplication,we can use the algebraic identity $(x + a)(x + b) = x^2 + (a + b)x + ab$.We can express t

Vedclass · Accepted Answer

$8835$

Vedclass · Answer

(A) To evaluate $93 	imes 95$ without direct multiplication,we can use the algebraic identity $(x + a)(x + b) = x^2 + (a + b)x + ab$.We can express the numbers as:$93 = 90 + 3$$95 = 90 + 5$Now,substitute these into the identity where $x = 90$,$a = 3$,and $b = 5$:$(90 + 3)(90 + 5) = (90)^2 + (3 + 5)(90) + (3 	imes 5)$Calculate each term:$(90)^2 = 8100$$(3 + 5)(90) = 8 	imes 90 = 720$$(3 	imes 5) = 15$Adding these values together:$8100 + 720 + 15 = 8835$Therefore,$93 	imes 95 = 8835$.

Evaluate the following product without multiplying directly:
$93 \times 95$

Similar Questions

Evaluate $(65)^{2}$.

Classify the following as a constant,linear,quadratic,or cubic polynomial:
$3$

Factorise the expression: $\frac{x^{2}}{4}+\frac{3 x y}{5}+\frac{9 y^{2}}{25}$

Determine the degree of the following polynomial:
$2x - 1$

Write the degree of the following polynomial:
$7 x^{3}-9 x^{2}+4 x-22$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Evaluate the following product without multiplying directly:$93 \times 95$